Commit e6a2e535def1797ac78ecaf313421524fcacd709

Authored by Francisco Coelho
1 parent 353a8086
Exists in master

pausa forçada para atualizar o meu (fc) sistema :D

text/paper_01/pre-paper.pdf
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text/paper_01/pre-paper.tex
@@ -74,6 +74,7 @@ citecolor=blue, @@ -74,6 +74,7 @@ citecolor=blue,
74 \newcommand{\probfact}[2]{\ensuremath{#1\!::\!#2}} 74 \newcommand{\probfact}[2]{\ensuremath{#1\!::\!#2}}
75 \newcommand{\tcgen}[1]{\ensuremath{\widehat{#1}}} 75 \newcommand{\tcgen}[1]{\ensuremath{\widehat{#1}}}
76 \newcommand{\lfrac}[2]{\ensuremath{{#1}/{#2}}} 76 \newcommand{\lfrac}[2]{\ensuremath{{#1}/{#2}}}
  77 +\newcommand{\condsymb}[2]{\ensuremath{p{#1}\_{#2}}}
77 78
78 \newcommand{\todo}[1]{{\color{red!50!black}(\emph{#1})}} 79 \newcommand{\todo}[1]{{\color{red!50!black}(\emph{#1})}}
79 \newcommand{\remark}[2]{\uwave{#1}~{\color{green!40!black}(\emph{#2})}} 80 \newcommand{\remark}[2]{\uwave{#1}~{\color{green!40!black}(\emph{#2})}}
@@ -781,7 +782,15 @@ We continue with the specification from Equation \eqref{eq:example.1}. @@ -781,7 +782,15 @@ We continue with the specification from Equation \eqref{eq:example.1}.
781 % 782 %
782 \subsection{An example involving Bayesian networks} 783 \subsection{An example involving Bayesian networks}
783 784
784 -As it turns out, our framework is suitable to deal with more sophisticated cases, for example cases involving Bayesian networks. In order to illustrate this, in this section we see how the classical example of the Burglary, Earthquake, Alarm \cite{Judea88} works in our setting. This example is a commonly used example in Bayesian networks because it illustrates reasoning under uncertainty. The gist of example is given in \cref{Figure_Alarm}. It involves a simple network of events and conditional probabilities. 785 +\franc{Cometários:}
  786 +\begin{itemize}
  787 + \item Há uma macro, $\backslash\text{pr}\{A\}$, para denotar a função de probabilidade, $\pr{A}$ em vez de $P(A)$. Já agora, para a condicional também há um comando, $\backslash\text{given}$: $\pr{A \given B}$.
  788 + \item E, claro, para factos+probabilidades: $\probfact{p}{a}$.
  789 + \item A designação dos `pesos' não está consistente: $pj\_a$ e $a\_be$. Fiz uma macro (hehe) para sistematizar isto: \condsymb{a}{bnc}
  790 +\end{itemize}
  791 +
  792 +
  793 +As it turns out, our framework is suitable to deal with more sophisticated cases, \replace{for example}{in particular} cases involving Bayesian networks. In order to illustrate this, in this section we see how the classical example of the Burglary, Earthquake, Alarm \cite{Judea88} works in our setting. This example is a commonly used example in Bayesian networks because it illustrates reasoning under uncertainty. The gist of example is given in \cref{Figure_Alarm}. It involves a simple network of events and conditional probabilities.
785 794
786 The events are: Burglary ($B$), Earthquake ($E$), Alarm ($A$), Mary calls ($M$) and John calls ($J$). The initial events $B$ and $E$ are assumed to be independent events that occur with probabilities $P(B)$ and $P(E)$, respectively. There is an alarm system that can be triggered by either of the initial events $B$ and $E$. The probability of the alarm going off is a conditional probability given that $B$ and $E$ have occurred. One denotes these probabilities, as per usual, by $P(A|B)$, and $P(A|E)$. There are two neighbours, Mary and John who have agreed to call if they hear the alarm. The probability that they do actually call is also a conditional probability denoted by $P(M|A)$ and $P(J|A)$, respectively. 795 The events are: Burglary ($B$), Earthquake ($E$), Alarm ($A$), Mary calls ($M$) and John calls ($J$). The initial events $B$ and $E$ are assumed to be independent events that occur with probabilities $P(B)$ and $P(E)$, respectively. There is an alarm system that can be triggered by either of the initial events $B$ and $E$. The probability of the alarm going off is a conditional probability given that $B$ and $E$ have occurred. One denotes these probabilities, as per usual, by $P(A|B)$, and $P(A|E)$. There are two neighbours, Mary and John who have agreed to call if they hear the alarm. The probability that they do actually call is also a conditional probability denoted by $P(M|A)$ and $P(J|A)$, respectively.
787 796
@@ -856,7 +865,7 @@ The events are: Burglary ($B$), Earthquake ($E$), Alarm ($A$), Mary calls ($M$) @@ -856,7 +865,7 @@ The events are: Burglary ($B$), Earthquake ($E$), Alarm ($A$), Mary calls ($M$)
856 \end{figure} 865 \end{figure}
857 866
858 867
859 -Considering the probabilities given in \cref{Figure_Alarm} we obtain the following specification 868 +Considering the probabilities given in \cref{Figure_Alarm} we obtain the following spe\-ci\-fi\-ca\-tion
860 869
861 \begin{equation*} 870 \begin{equation*}
862 \begin{aligned} 871 \begin{aligned}
@@ -871,8 +880,8 @@ For the table giving the probability $P(M|A)$ we obtain the specification: @@ -871,8 +880,8 @@ For the table giving the probability $P(M|A)$ we obtain the specification:
871 880
872 \begin{equation*} 881 \begin{equation*}
873 \begin{aligned} 882 \begin{aligned}
874 - &\probfact{0.9}{pm\_a},\cr  
875 - &\probfact{0.05}{pm\_na},\cr 883 + \probfact{0.9}{pm\_a}&,\cr
  884 + \probfact{0.05}{pm\_na}&,\cr
876 m & \leftarrow a, pm\_a,\cr 885 m & \leftarrow a, pm\_a,\cr
877 \neg m & \leftarrow a, \neg pm\_a. 886 \neg m & \leftarrow a, \neg pm\_a.
878 \end{aligned} 887 \end{aligned}